3.15.89 \(\int \frac {(a+b x)^2}{a c+(b c+a d) x+b d x^2} \, dx\)

Optimal. Leaf size=26 \[ \frac {b x}{d}-\frac {(b c-a d) \log (c+d x)}{d^2} \]

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Rubi [A]  time = 0.02, antiderivative size = 26, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.069, Rules used = {626, 43} \begin {gather*} \frac {b x}{d}-\frac {(b c-a d) \log (c+d x)}{d^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^2/(a*c + (b*c + a*d)*x + b*d*x^2),x]

[Out]

(b*x)/d - ((b*c - a*d)*Log[c + d*x])/d^2

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 626

Int[((d_) + (e_.)*(x_))^(m_.)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[(d + e*x)^(m + p)*(a
/d + (c*x)/e)^p, x] /; FreeQ[{a, b, c, d, e, m}, x] && NeQ[b^2 - 4*a*c, 0] && EqQ[c*d^2 - b*d*e + a*e^2, 0] &&
IntegerQ[p]

Rubi steps

\begin {align*} \int \frac {(a+b x)^2}{a c+(b c+a d) x+b d x^2} \, dx &=\int \frac {a+b x}{c+d x} \, dx\\ &=\int \left (\frac {b}{d}+\frac {-b c+a d}{d (c+d x)}\right ) \, dx\\ &=\frac {b x}{d}-\frac {(b c-a d) \log (c+d x)}{d^2}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 25, normalized size = 0.96 \begin {gather*} \frac {(a d-b c) \log (c+d x)}{d^2}+\frac {b x}{d} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^2/(a*c + (b*c + a*d)*x + b*d*x^2),x]

[Out]

(b*x)/d + ((-(b*c) + a*d)*Log[c + d*x])/d^2

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(a+b x)^2}{a c+(b c+a d) x+b d x^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(a + b*x)^2/(a*c + (b*c + a*d)*x + b*d*x^2),x]

[Out]

IntegrateAlgebraic[(a + b*x)^2/(a*c + (b*c + a*d)*x + b*d*x^2), x]

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fricas [A]  time = 0.40, size = 25, normalized size = 0.96 \begin {gather*} \frac {b d x - {\left (b c - a d\right )} \log \left (d x + c\right )}{d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/(a*c+(a*d+b*c)*x+b*d*x^2),x, algorithm="fricas")

[Out]

(b*d*x - (b*c - a*d)*log(d*x + c))/d^2

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giac [A]  time = 0.16, size = 27, normalized size = 1.04 \begin {gather*} \frac {b x}{d} - \frac {{\left (b c - a d\right )} \log \left ({\left | d x + c \right |}\right )}{d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/(a*c+(a*d+b*c)*x+b*d*x^2),x, algorithm="giac")

[Out]

b*x/d - (b*c - a*d)*log(abs(d*x + c))/d^2

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maple [A]  time = 0.14, size = 32, normalized size = 1.23 \begin {gather*} \frac {a \ln \left (d x +c \right )}{d}-\frac {b c \ln \left (d x +c \right )}{d^{2}}+\frac {b x}{d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^2/(a*c+(a*d+b*c)*x+b*d*x^2),x)

[Out]

b/d*x+1/d*ln(d*x+c)*a-1/d^2*ln(d*x+c)*b*c

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maxima [A]  time = 1.01, size = 26, normalized size = 1.00 \begin {gather*} \frac {b x}{d} - \frac {{\left (b c - a d\right )} \log \left (d x + c\right )}{d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/(a*c+(a*d+b*c)*x+b*d*x^2),x, algorithm="maxima")

[Out]

b*x/d - (b*c - a*d)*log(d*x + c)/d^2

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mupad [B]  time = 0.04, size = 25, normalized size = 0.96 \begin {gather*} \frac {\ln \left (c+d\,x\right )\,\left (a\,d-b\,c\right )}{d^2}+\frac {b\,x}{d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x)^2/(a*c + x*(a*d + b*c) + b*d*x^2),x)

[Out]

(log(c + d*x)*(a*d - b*c))/d^2 + (b*x)/d

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sympy [A]  time = 0.17, size = 20, normalized size = 0.77 \begin {gather*} \frac {b x}{d} + \frac {\left (a d - b c\right ) \log {\left (c + d x \right )}}{d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**2/(a*c+(a*d+b*c)*x+b*d*x**2),x)

[Out]

b*x/d + (a*d - b*c)*log(c + d*x)/d**2

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